Integrand size = 22, antiderivative size = 52 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\frac {x^2}{b \sqrt {d x^2}}-\frac {\sqrt {a} x \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{b^{3/2} \sqrt {d x^2}} \]
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Time = 0.01 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {15, 327, 211} \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\frac {x^2}{b \sqrt {d x^2}}-\frac {\sqrt {a} x \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{b^{3/2} \sqrt {d x^2}} \]
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Rule 15
Rule 211
Rule 327
Rubi steps \begin{align*} \text {integral}& = \frac {x \int \frac {x^2}{a+b x^2} \, dx}{\sqrt {d x^2}} \\ & = \frac {x^2}{b \sqrt {d x^2}}-\frac {(a x) \int \frac {1}{a+b x^2} \, dx}{b \sqrt {d x^2}} \\ & = \frac {x^2}{b \sqrt {d x^2}}-\frac {\sqrt {a} x \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{b^{3/2} \sqrt {d x^2}} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.15 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\frac {\sqrt {d x^2}}{b d}-\frac {\sqrt {a} \arctan \left (\frac {\sqrt {b} \sqrt {d x^2}}{\sqrt {a} \sqrt {d}}\right )}{b^{3/2} \sqrt {d}} \]
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Time = 2.89 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.73
method | result | size |
default | \(\frac {x \left (\sqrt {a b}\, x -a \arctan \left (\frac {b x}{\sqrt {a b}}\right )\right )}{\sqrt {d \,x^{2}}\, b \sqrt {a b}}\) | \(38\) |
pseudoelliptic | \(\frac {-a \arctan \left (\frac {b \sqrt {d \,x^{2}}}{\sqrt {a b d}}\right ) d +\sqrt {d \,x^{2}}\, \sqrt {a b d}}{b d \sqrt {a b d}}\) | \(49\) |
risch | \(\frac {x^{2}}{b \sqrt {d \,x^{2}}}+\frac {x \sqrt {-a b}\, \ln \left (-\sqrt {-a b}\, x -a \right )}{2 \sqrt {d \,x^{2}}\, b^{2}}-\frac {x \sqrt {-a b}\, \ln \left (\sqrt {-a b}\, x -a \right )}{2 \sqrt {d \,x^{2}}\, b^{2}}\) | \(81\) |
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Time = 0.24 (sec) , antiderivative size = 126, normalized size of antiderivative = 2.42 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\left [\frac {d \sqrt {-\frac {a}{b d}} \log \left (\frac {b x^{2} - 2 \, \sqrt {d x^{2}} b \sqrt {-\frac {a}{b d}} - a}{b x^{2} + a}\right ) + 2 \, \sqrt {d x^{2}}}{2 \, b d}, -\frac {d \sqrt {\frac {a}{b d}} \arctan \left (\frac {\sqrt {d x^{2}} b \sqrt {\frac {a}{b d}}}{a}\right ) - \sqrt {d x^{2}}}{b d}\right ] \]
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Time = 1.38 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.04 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\begin {cases} \frac {2 \left (- \frac {a d^{2} \operatorname {atan}{\left (\frac {\sqrt {d x^{2}}}{\sqrt {\frac {a d}{b}}} \right )}}{2 b^{2} \sqrt {\frac {a d}{b}}} + \frac {d \sqrt {d x^{2}}}{2 b}\right )}{d^{2}} & \text {for}\: d \neq 0 \\\tilde {\infty } x^{4} & \text {otherwise} \end {cases} \]
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Time = 0.33 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.94 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=-\frac {\frac {a d^{2} \arctan \left (\frac {\sqrt {d x^{2}} b}{\sqrt {a b d}}\right )}{\sqrt {a b d} b} - \frac {\sqrt {d x^{2}} d}{b}}{d^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.77 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=-\frac {a \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{\sqrt {a b} b \sqrt {d} \mathrm {sgn}\left (x\right )} + \frac {x}{b \sqrt {d} \mathrm {sgn}\left (x\right )} \]
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Time = 5.38 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.71 \[ \int \frac {x^3}{\sqrt {d x^2} \left (a+b x^2\right )} \, dx=\frac {\sqrt {x^2}}{b\,\sqrt {d}}-\frac {\sqrt {a}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x^2}}{\sqrt {a}}\right )}{b^{3/2}\,\sqrt {d}} \]
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